/** * @brief Codeforces Round #279 (Div. 2) d * @file d.cpp * @author 面碼 * @created 2014/12/09 10:58 * @edited 2014/12/09 10:58 * @type math greedy * @note 自己的AC不了，參考別人的，重點(diǎn)是2和3都是質(zhì)數(shù)，所以可以使用貪心求解。 */#include #include #include #include #include using namespace std;#define max(a, b) ((a) > (b) ? (a) : (b))#define min(a, b) ((a) > (b) ? (b) : (a)) #define abs(a) ((a) > 0 ? (a) : (0 - (a)))#define CLR(vec) memset(vec, 0, sizeof(vec))#define MAXN 4000#ifdef DEBUGifstream in;ofstream out;#define CIN in#define COUT out#else#define CIN cin#define COUT cout#endiftypedef long long int ll;ll a, b, c, d;ll ans, a1, b1, c1, d1;ll c12, c13, c22, c23;int main(void){ ios_base::sync_with_stdio(0);#ifdef DEBUG CIN.open("./in", ios::in); COUT.open("./out", ios::out);#endif CIN >> a >> b >> c >> d; ans = 0; a1 = a, b1 = b, c1 = c, d1 = d; c13 = 0; c23 = 0; while(0 == a1%3 && a1) a1 /= 3, c13++; while(0 == b1%3 && b1) b1 /= 3, c13++; while(0 == c1%3 && c1) c1 /= 3, c23++; while(0 == d1%3 && d1) d1 /= 3, c23++; while(c13 > c23 && 0 == a%3 && a) c13--, a = a*2/3, ans++; while(c13 > c23 && 0 == b%3 && b) c13--, b = b*2/3, ans++; while(c13 < c23 && 0 == c%3 && c) c23--, c = c*2/3, ans++; while(c13 < c23 && 0 == d%3 && d) c23--, d = d*2/3, ans++; a1 = a, b1 = b, c1 = c, d1 = d; c12 = 0; c22 = 0; while(0 == a1%2 && a1) a1 /= 2, c12++; while(0 == b1%2 && b1) b1 /= 2, c12++; while(0 == c1%2 && c1) c1 /= 2, c22++; while(0 == d1%2 && d1) d1 /= 2, c22++; while(c12 > c22 && 0 == a%2 && a) c12--, a /= 2, ans++; while(c12 > c22 && 0 == b%2 && b) c12--, b /= 2, ans++; while(c12 < c22 && 0 == c%2 && c) c22--, c /= 2, ans++; while(c12 < c22 && 0 == d%2 && d) c22--, d /= 2, ans++; if(a *b != c*d){ COUT << "-1\n"; return 0; } COUT << ans << "\n"; COUT << a << " " << b << "\n"; COUT << c << " " << d << "\n"; return 0;}
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